What is the bus part of the breadboard?
The top holes are the top bus and they are all connected.
The bottom holes are the bottom bus and they are all connected.
Top bus and bottom bus are not connected with each other.
How squeezing the foam brightens the LED
The piece of foam conducts electricity. It also has resistance, and the resistance decreases when the foam is squeezed. Since the foam piece and the resistor are in series, when the foam resistance decreases the overall resistance of the circuit decreases, causing the LED to be brighter.
Capacitor leaks current as it charges
The capacitor is like a bucket when electricity goes through in capacitor it lets the electricity out the more the capacitor fills up the less electricity comes out when the capacitor is full it stops leaking electricity
How does the circuit work?
it starts with the negitive terminal to black wire to bottom bus then it connects to yellow wire. connects to collom 12 on the top terminal strip. goes up the LED then goes into the bulb then goes down into the collom 11 then travles down the resister then that travles up to the top bus then it goes down to the positive wire. then it goes back into the battery it is a continouis path
Using the Op Amp as a Comparator
Inside the IC there are two op amps. They can act as comparators. When the non-inverting pin has higher voltage than the inverting pin, the op amp outputs 9 volts. When the non-inverting pin has lower voltage than the inverting pin, the op amp outputs 0 volts.
How the pressure sensor circuit works
When the potentiometer is turned all the way clockwise, its resistance is zero, making the voltage of the inverting pin very small, so the op amp outputs 9 volts. As you turn the potentiometer counterclockwise, its resistance goes up, making the voltage of the inverting pin become higher. At some point, the voltage at the inverting pin will become higher than the voltage at the non-inverting pin, so the op amp will output 0 volts. However, if you squeeze the foam, its resistance will go down, causing the voltage at the non-inverting pin to be higher than the inverting pin.